MRMaschinenbaurechner

Braking torque calculator

Determine the braking torque to size a holding brake or a stopping brake: static as a safety margin against a driving load torque (M_Br = M_Load·f_SB) and dynamic for decelerating a total inertia from a given speed to standstill within a set time (M_Br = J·ω/t + M_Load). The calculator also returns the braking energy per stop and the resulting permissible braking frequency, live with every input and with a traffic-light rating against a chosen braking torque.

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Model: ideal brake with constant braking torque, decelerating from n to 0 at constant angular deceleration. Friction-coefficient scatter, response and delay times, gear efficiency between brake and load, and thermal limit cases are not included and must be checked separately. Sizing tool, not a safety-related proof.

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Formulas and fundamentals

Sizing a holding brake (static check)

The static check secures holding against a driving load torque, for example on a lifting axis or an inclined drive. The required braking torque is:

M_Br,req = M_Load·f_SB

With the load torque M_Load at the brake and the required safety factor f_SB. Conversely, the available safety of a chosen braking torque is:

f_SB,avail = M_Br,avail/M_Load

Typical safety factors range from 1.5 to 2 depending on application and regulation, and higher where personal safety is involved.

Sizing a stopping brake (dynamic check)

The dynamic check sizes the brake for deceleration. From the initial speed n follows the angular frequency:

ω = 2π·n/60

To bring the total inertia J_tot referred to the brake from ω to zero within the braking time t, a deceleration torque is needed:

M_a = J_tot·ω/t

If a driving load torque acts at the same time, the brake must absorb it as well:

M_Br,req = J_tot·ω/t + M_Load

A resisting load torque would instead reduce the required braking torque.

Braking energy and switching frequency

For thermal sizing the braking energy per stop matters:

W_Br = ½·J·ω²

This rotational energy is converted into friction heat during deceleration; a driving load torque over the braking distance adds to it. From the thermally permissible braking work per hour W_th/h,perm and W_Br follows the permissible braking frequency as:

stops per hour = W_th/h,perm / W_Br

In many applications this limits the cycle rate more strongly than the braking torque alone.

Worked example

Static: a driving load torque of M_Load = 25 Nm is to be held with a safety factor f_SB = 1.5. The required braking torque is M_Br,req = 25·1.5 = 37.5 Nm. A chosen brake with M_Br,avail = 50 Nm passes the check; its available safety is 50/25 = 2.0.

Dynamic: a total inertia J_tot = 0.15 kg·m² is to be decelerated from n = 1400 rpm to zero within t = 0.5 s, with no driving load torque. With ω = 2π·1400/60 = 146.6 rad/s this gives M_Br,req = 0.15·146.6/0.5 = 43.98 Nm.

The braking energy per stop is W_Br = ½·0.15·146.6² ≈ 1612 J. With a thermally permissible braking work of, say, 100,000 J per hour, the permissible braking frequency is about 62 stops per hour - above this rate the brake overheats even though the braking torque is sufficient.

Frequently asked questions

When do I use the static case, when the dynamic one?

Static when the brake must safely hold a stationary but driving load (holding brake on a lifting axis). Dynamic when it must actively decelerate a rotating mass (stopping brake). If a brake has to do both, run both checks and the larger required braking torque governs.

How do I choose the safety factor f_SB?

The factor covers friction-coefficient scatter, wear and uncertainty in the load torque. For holding brakes 1.5 to 2.0 is common; for passenger or load lifts and safety-related functions higher, often normatively prescribed values apply. The calculator uses the entered value unchanged.

Why does the dynamic braking torque rise with speed?

Because the deceleration torque M_a = J·ω/t is proportional to the angular frequency ω = 2π·n/60. Twice the speed means twice the deceleration torque for the same braking time. Shorter braking times increase it further, since t is in the denominator - an emergency stop with small t demands considerably more torque than a gentle stop.

Why does the braking frequency limit the brake on top of torque?

Each stop converts the energy W_Br = ½·J·ω² into heat. At a high cycle rate this heat accumulates faster than the brake can dissipate it. If the braking work per hour exceeds the thermally permissible limit, friction lining and brake overheat - regardless of whether the braking torque is sufficient. So besides torque, always check the thermal limit.

What is the difference between a driving and a resisting load torque?

A driving load torque (for example gravity on a lifting axis) acts in the direction of motion and must be absorbed by the brake as well - it increases the required braking torque. A resisting load torque (friction, process force) opposes the motion and would reduce it. The calculator adds the entered load torque; a resisting torque should conservatively be set to 0.

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