Shaft Calculation per DIN 743
Load capacity verification for steel shafts and axles right in your browser: notch effect, component fatigue strength and safety factors against fatigue fracture and permanent deformation, with every intermediate value on display, live with every input.
Calculation
Look up guideline values for KV
| Process | d = 8 to 25 mm | d = 25 to 40 mm |
|---|---|---|
| Nitriding | 1,15 – 1,25 | 1,10 – 1,15 |
| Case hardening | 1,20 – 2,10 | 1,10 – 1,50 |
| Carbonitriding | 1,10 – 1,90 | 1,00 – 1,40 |
| Roller burnishing | 1,20 – 1,40 | 1,10 – 1,25 |
| Shot peening | 1,10 – 1,30 | 1,10 – 1,20 |
| Induction or flame hardening | 1,20 – 1,60 | 1,10 – 1,40 |
Extract from DIN 743-2. Without your own test value, take the lower end of the range. Between d = 25 and 40 mm the effect decreases linearly, above 40 mm KV approaches 1.0. For an untreated surface KV = 1.0.
Maximum value = |mean| + amplitude. Only the amplitude counts for fatigue failure: entering an alternating load as a mean value by mistake yields an infinite safety factor without any warning.
Split by what actually changes at the notch. Rotating shaft: bending goes entirely into the amplitude, mean 0. Stationary shaft under a fixed load: the other way round. Torsion in one direction: the steady torque into the mean, only its fluctuation into the amplitude; in reversing duty everything into the amplitude. Include an application factor KA for shocks beforehand - on the amplitude for bending, as amplitude (KA − 1)·Mt for steady torsion.
Model: DIN 743 for shafts and axles made of steel, not welded, −40 to +150 °C, corrosion-free environment. One cross-section is analysed under tension/compression, bending and torsion, assumed to be in phase, against the fatigue limit at 10⁷ load cycles. Transverse shear, buckling, residual stresses and finite-life fatigue are not covered; a compressive mean stress is calculated without the special case of the standard and therefore stays on the safe side.
Results
Intermediate values
- K1 (σB)
- 0.871
- K1 (σS)
- 0.797
- σB(d) [N/mm²]
- 958.5
- σS(d) [N/mm²]
- 717.4
- σmv [N/mm²]
- 110.3
- τmv [N/mm²]
- 63.7
- Cross section A [mm²]
- 1,257
- Section modulus Wb [mm³]
- 6,283
- Section modulus Wt [mm³]
- 12,566
| Quantity | Tension/compr. | Bending | Torsion |
|---|---|---|---|
| σm or τm in N/mm² | 0 | 0 | 63.7 |
| σa or τa in N/mm² | 0 | 79.6 | 15.9 |
| σmax or τmax in N/mm² | 0 | 79.6 | 79.6 |
| Concentration factor α | 1.968 | 1.801 | 1.405 |
| Stress gradient G′ in 1/mm | 0.874 | 0.874 | 0.383 |
| Support number n | 1.043 | 1.043 | 1.028 |
| Fatigue notch factor β | 1.887 | 1.727 | 1.366 |
| Size factor K2 | 1 | 0.888 | 0.888 |
| Roughness factor KF | 0.895 | 0.895 | 0.94 |
| Total influence K | 2.004 | 2.061 | 1.602 |
| Fatigue strength WK in N/mm² | 191.3 | 232.5 | 179.5 |
| Mean stress sensitivity ψ | 0.111 | 0.138 | 0.103 |
| Static support K2F | 1 | 1.2 | 1.2 |
| Increase factor γF | 1.05 | 1.05 | 1 |
| Yield limit FK in N/mm² | 753.3 | 903.9 | 497 |
| Tolerable amplitude ADK in N/mm² | 191.3 | 195.2 | 99.4 * |
* limited by the yield limit (kink in the Haigh diagram)
Sketch: notch case
Fatigue limit diagram
Governing direction with the highest amplitude utilisation. The distance between the operating point and the limit line is the reserve against fatigue failure; for loading case 2 the evaluation follows the ray through the origin.
Report PDF with inputs, calculation steps, results and the underlying model assumptions and limits.
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Formulas and fundamentals
Verification concept per DIN 743
DIN 743 requires two separate verifications for every critical cross section of a shaft or axle: the safety against fatigue fracture S_D from the stress amplitudes and the fatigue strength of the notched component, and the safety against permanent deformation S_F from the maximum stresses and the component yield limit. The minimum safety factor of the standard is S_min = 1.2; it only covers the uncertainty of the method itself, so values of 1.5 to 2.0 are commonly agreed in practice depending on load knowledge and failure consequences.
Nominal stresses in the notch cross section
The starting point are the nominal stresses in the notch cross section, always computed with the notch root diameter d:
Each split into mean value and amplitude. For a cross hole, net section moduli apply; for a keyway and an interference fit the full circular cross section is used because the weakening is fully contained in the fatigue notch factor. On the notch-free section of a plain shaft there is nothing to deduct anyway.
Fatigue notch factor and component fatigue strength
For shoulders, circumferential grooves and cross holes the fatigue notch factor β follows from the stress concentration factor α and the support number n, which captures the material's micro-support effect via the relative stress gradient G′:
For keyways and interference fits the standard instead provides experimentally determined β values that depend only on the tensile strength at the component and are converted from the 40 mm specimen diameter to the component diameter with the geometric size factor K3: β_σ ≈ 3.0·(σ_B(d)/1000)^0.38 for the keyway and β_σ ≈ 2.7·(σ_B(d)/1000)^0.43 for the interference fit. The notch-free section of a plain shaft carries β = 1 by definition. Together with the size factor K2, the surface roughness factor K_F (input as Rz, not Ra!) and the surface treatment factor K_V, the total influence factor K is formed, giving the component fatigue strength:
Size factor K1 and calculated safety factors
The technological size factor K1 converts the material properties from the 16 mm reference diameter to the effective diameter d_eff - with different factors for tensile strength and yield strength, a frequent source of errors. Via the equivalent mean stress σ_mv and the mean stress sensitivity ψ the tolerable amplitude σ_ADK follows, either for loading case 1 (constant mean stress) or case 2 (constant σ_m/σ_a ratio, usually more conservative). At high mean stresses the yield limit caps the amplitude - the calculator detects this kink in the Haigh diagram automatically and flags the affected direction. The safety factors follow from:
and analogously S_F with the maximum stresses and component yield limits.
Fatigue limit diagram and rating
The calculator draws one Haigh diagram, for the governing loading direction - the one with the highest amplitude utilisation: the tolerable amplitude over the equivalent mean stress σ_mv. The limit line is ADK(σ_m) = min(σ_WK − ψ·σ_m, FK − σ_m) - the falling branch of the fatigue strength and, beyond the kink, the cap imposed by the component yield limit. The operating point from the inputs and the tolerable point on the limit line are marked; their distance shows the reserve of that one direction. If several load types carry amplitude at once, the reported safety factor S_D is lower, because it combines the directions - the diagram then shows the governing one, not the overall result. Where the tolerable point lies depends on the loading case: for case 1 vertically above the operating point, for case 2 on the ray through it from the origin.
The rating is against the selected minimum safety factor S_min. If S_D or S_F falls below it, the check is not satisfied and the indicator is red - even when the safety factor is still above 1.0 and neither fracture nor yielding occurs numerically. Amber is used only just above S_min, that is satisfied without appreciable reserve.
Worked example
Reference example (University of Bayreuth, ZN743): shaft shoulder with D = 50 mm, d = 40 mm, r = 3 mm made of quenched and tempered 36CrNiMo4 (σ_B = 1100 N/mm², σ_S = 900 N/mm² at 16 mm), Rz = 5 µm, d_eff = 50 mm. Loading as nominal stresses: tension/compression 200 ± 50, bending 300 ± 60, torsion 100 ± 40 N/mm², loading case 1.
The calculation yields stress concentration factors α = 1.97 / 1.80 / 1.40 (tension, bending, torsion), support numbers around 1.03 and thus fatigue notch factors β = 1.89 / 1.73 / 1.37. With K1(σ_B) = 0.87, K2 = 0.89 and K_F ≈ 0.90 the component fatigue strengths come to about 191 / 232 / 179 N/mm² and the tolerable amplitudes to 133 / 159 / 148 N/mm² at an equivalent mean stress of 529 N/mm².
Result: S_D = 1.25 and S_F = 1.28 - both above the minimum safety factor of 1.2, the verification is passed. The source uses the simplifying convention of applying K1(σ_B) to the yield strength as well and obtains S_F = 1.40; this calculator uses the separate K1 factors as intended by the standard and is therefore on the safe side.
Frequently asked questions
What minimum safety factor does DIN 743 require?
The standard states S_min = 1.2 for both verifications. This value only covers the uncertainty of the calculation method. In practice, higher values of 1.5 to 2.0 are agreed depending on how well the loads are known and the consequences of a failure - the minimum safety factor is therefore adjustable in the calculator.
Why are two verifications needed - fatigue and yielding?
Both verifications are mandatory and address different failure modes: the dynamic verification compares the stress amplitudes with the component fatigue strength (fatigue fracture after many load cycles), the static one compares the maximum stresses with the component yield limit (permanent deformation at peak load). At high mean loads the static verification often governs.
Which notch case do I have to choose?
The one that actually sits at the cross section being verified - the calculation always covers one location of the shaft, never the whole shaft. Shaft shoulder: step in diameter with a fillet, d is the small diameter, D the large one, r the fillet radius. Circumferential groove: undercut or round groove in an otherwise continuous diameter, D is the outer diameter, d the groove root, r the groove root radius. For the same geometry the groove is the sharper notch, because the notch root is constricted from both sides. Transverse hole: lubrication or pin hole across the shaft, r is the hole radius, and the nominal stresses follow from the net section moduli. Keyway: hub seat with a groove, without a radius input. Interference fit: hub seat without a key, also with the seat diameter only. Plain shaft: notch-free section, for example the free shaft end or the span between two notches. Where several notches meet, calculate each cross section separately and take the least favourable one; superimposed notches are not covered by DIN 743.
What do loading case 1 and case 2 mean?
The cases describe how the mean stress behaves when the load increases. Case 1: the mean stress stays constant, only the amplitude grows. Case 2: the ratio of mean stress to amplitude stays constant, both grow together. Case 2 is usually more critical and therefore the conservative choice when in doubt - the calculator defaults to case 2.
Why are the material properties converted with K1?
Tabulated material properties apply to the 16 mm reference diameter. Larger cross sections harden less thoroughly during quenching and tempering, so the strength drops. The technological size factor K1 captures this via the effective diameter d_eff - with different factors for tensile and yield strength. Forgetting K1 is the most common mistake in DIN 743 calculations.
When may I tick “strength measured on the component”?
Only when the properties were determined on the finished component in its final condition - for example by a hardness test on the quenched and tempered part converted to tensile strength, or by a tensile test on a specimen taken from it. Two things then belong together: enter your measured value in the σB and σS fields, and tick the box. The tick alone only says that no second conversion from the reference diameter takes place (K1 = 1) - if the table values for 16 mm still stand alongside it, you are claiming that your component is as strong as a 16 mm specimen. That is on the unsafe side, because on a large shaft one usually measures less. An inspection certificate for the material, a value measured on the blank or a hardness figure from the data sheet are not sufficient: they say nothing about the through-hardening of your cross section. The option matters - for a quenched and tempered steel with d_eff = 50 mm, K1 = 0.87 for tensile strength and 0.80 for yield strength apply otherwise - which is why the statement and its justification appear in the verification PDF.
My steel is not in the list - what then?
Simply enter its properties. The σB and σS fields always sit below the selection and initially show the values of the chosen table row; as soon as you change one of them, the selection switches to “Free (own values)” and the calculator uses your figures. Pick the matching material group as well, because it decides how steeply K1 reduces the properties with the effective diameter - case-hardening and nitriding steels are only reachable this way. You do not have to enter the three fatigue limits: the calculator derives them from the tensile strength per DIN 743-3 (σzdW = 0.4·σB, σbW = 0.5·σB, τtW = 0.3·σB) - the same ratios every row of the table observes. Do check whether your data sheet value applies to the 16 mm reference diameter (then leave the box unticked and K1 converts) or was measured on the component (then tick it).
Do I enter Rz or Ra?
The roughness factor K_F requires the mean roughness depth Rz in µm, not the arithmetic mean roughness Ra. Entering Ra would give far too favourable results. Typical values: polished 1, ground 4, fine-turned 10, turned 25, mill scale 200 µm. For keyways and interference fits the calculator sets K_F = 1 because the reference roughness is already contained in the experimental fatigue notch factor.
Why does the keyway need no notch radius?
There is no closed-form stress concentration formula for keyways. DIN 743 instead uses experimentally determined fatigue notch factors that depend only on the tensile strength of the component and are converted from the 40 mm specimen diameter to the component diameter with the size factor K3. The nominal stresses are formed with the full circular cross section. With two keyways in the same cross section, the fatigue notch factor increases by a factor of 1.15.
How do I verify an interference fit?
Choose the notch case interference fit and enter the seat diameter only. Here too there is no stress concentration factor: the notch effect does not arise from a geometry of the shaft but at the end of the hub seat, where the force flow enters the hub, and it already contains the fretting load in that run-in zone. DIN 743 gives an experimental value that depends only on the tensile strength at the component: β_σ ≈ 2.7·(σ_B(d)/1000 N/mm²)^0.43 and β_τ ≈ 0.65·β_σ, referred to the 40 mm specimen diameter and converted via K3. The value stays below that of the keyway - a hub seat without a groove is the milder notch. Two limits: it applies to a plain, non-stepped shaft, and the table in the standard covers 400 to 1200 N/mm². If the hub sits directly against a shaft shoulder, verify the shoulder instead - the press fit changes its notch effect only slightly.
What is the plain shaft notch case for?
For the cross section that carries no notch at all and can still be the critical one - the free shaft end, the span between two notches, or the location with the largest bending moment on a small diameter. The fatigue notch factor there is 1 by definition, since β is defined as the ratio of the fatigue strength of the unnotched specimen to that of the component. Size and roughness keep acting unchanged; they stand separately in K2 and K_F. There is no form factor and no support factor. Without this case you would have to invent a notch just to be able to calculate the plain cross section at all.
How are bending and torsion assessed together?
Not separately, but combined into one figure per verification. The normal stresses from tension/compression and bending are added because they act in the same direction; the shear stress from torsion enters quadratically: S_D = 1/√((σ_zda/σ_zdADK + σ_ba/σ_bADK)² + (τ_ta/τ_tADK)²), and S_F likewise with the maximum stresses and the component yield limits. Each direction is first referred to its own tolerable value, and only these utilisations are combined. Two consequences: the overall safety factor is always below that of every single direction, and the Haigh diagram shows only the governing direction, not the overall result. The mean stresses are combined beforehand via the distortion energy hypothesis into the equivalent mean stress σ_mv = √(σ_m² + 3·τ_m²); loading is assumed to be in phase.
What do the colours of the safety factors mean?
Red means the check is not satisfied: S_D or S_F is below the selected minimum safety factor S_min. This applies even when the factor is still above 1.0 and neither fatigue fracture nor yielding occurs numerically - the wording next to it distinguishes the two cases (“below S_min” versus “not OK”). Amber is used only just above S_min, that is satisfied without appreciable reserve. Green means satisfied with reserve. The colour therefore follows the verification, not the distance to fracture.
Which components does the verification apply to?
DIN 743 applies to non-welded steel shafts and axles at −40 to +150 °C in a non-corrosive environment, under tension/compression, bending and torsion (assumed in phase). The endurance limit refers to 10⁷ load cycles. Transverse shear, buckling and residual stresses are not covered explicitly by the method.
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